3z^2+1z+10=3

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Solution for 3z^2+1z+10=3 equation: 



3z^2+1z+10=3

We move all terms to the left:

3z^2+1z+10-(3)=0

We add all the numbers together, and all the variables

3z^2+z+7=0

a = 3; b = 1; c = +7;
Δ = b2-4ac
Δ = 12-4·3·7
Δ = -83
Delta is less than zero, so there is no solution for the equation

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